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In everyday life, we typically think of motion as a movement from one place to another. But to physicists, it is not that simple. Although motion is a movement from one point to another, what type of motion and its plane play an important part in physics.
Motion can be one dimensional, two dimensional, or three dimensional. For this explanation, we look at motion in one dimension, namelymotion (or movement) in a straight line.
Linear motionis a change in position from one point to another in astraight line in one dimension. Driving a car along a straight highway is an example of motion in one dimension.
Let’s look at displacement, velocity, and acceleration in more detail.
An object can only move in two directions in a straight line, namely forwards or backwards in our case.If we change the position of an object in a particular direction, we are causing adisplacement.
Because displacement is avector quantity, meaning it has a magnitude and a direction, it can be positive or negative. You can take any reference direction as positive or negative, but keep in mind which direction you choose as positive or negative. To calculate displacement, we use the following equation, where Δxis thedisplacement, xfis the final position, and xiis the initial position.
See our explanation,Scalar and Vector, for more info on scalar and vector quantities.
Velocity is achange in displacement over time.
We can calculate velocity using the following equation, where v is the velocity, Δx is the change in position, and Δt is the change in time.
The above equation is specifically foraverage velocity, which means it is the calculation of velocity over thewhole displacement divided by the total time. But what if you wanted to know the velocity at a certain instant of time and not over the whole period? This is where the concept of instantaneous velocity comes into play.
We can calculate the instantaneous velocity by applying the average velocity, but we have to narrow the time so that it approaches zero for that particular instant. Now, if you’re thinking that in order to calculate this, you would need to know some calculus, you are right! However, let’s discuss a few scenarios first.
If thevelocity is the same throughout the displacement, then theaverage velocity equals the instantaneous velocityat any point in time.
So, the instantaneous velocity for the above example is 7m/s (metres per second) as it is not changing at any instant of time.
Thegradientat any point in time of adisplacement-time graph is the velocityat that instant.
Look at the displacement-time graph below with displacement on the y-axis and time on the x-axis. Thecurveon the graph depicts thedisplacement over time.
To calculate the instantaneous velocity at point p1,我们take the gradient of the displacement-time curve and make it infinitely small so that it approaches 0. Here’s the calculation, wherex2is the final displacement, x1is the initial displacement, t2is the time at final displacement, and t1is the time at initial displacement.
If theacceleration is constant,我们can use one of thekinematics equations(equations of motion)to find the instantaneous velocity. Have a look at the equation below.
In the above equation, u is the initial velocity, and v is the instantaneous velocity at any instant of time t provided the acceleration remains constant for the whole duration of motion.
Acceleration is therate of change of velocity.
We can calculate the acceleration as follows:
Just like average velocity, the above equation is foraverage acceleration. So what if you wanted to calculate the acceleration at any point in time and not across a period? Let’s look at instantaneous acceleration.
Achange in velocity at any point in time is instantaneous acceleration. The calculation for instantaneous acceleration is similar to instantaneous velocity.
If thevelocity of a moving body is the same throughout the displacement, then theinstantaneous acceleration equals zeroat any point in time.
What is the instantaneous acceleration of a body if it moves at a constant velocity of 7m/s throughout its journey?
Solution
The instantaneous acceleration, in this case, is 0m/s2as there is no change in velocity. So, instantaneous acceleration for a body that has a constant velocity is 0.
Thegradientat any point in time of avelocity-time graph is the accelerationat that instant.
In the above velocity-time graph (velocity is on the y-axis and time is on the x-axis), thecurve is the velocity. Let’s say you want to calculate the acceleration at point p1. The gradient at point p1is the instantaneous acceleration, and you can calculate it as follows, where v2is thefinal velocity, v1is the initial velocity, t2is thetime at final velocity, and t1is thetime at initial velocity.
The velocity of a moving particle is given by v(t) = 20t - 5t2m/s. Calculate the instantaneous acceleration at t = 1, 2, 3, and 5s.
Since we know the change in velocity is acceleration, we need to take the derivative of the v(t) equation. Hence,
Plugging in the values for times 1, 2, 3, and 5 intgives:
With a bit of calculus and derivatives, you can find the instantaneous acceleration at point p1.
The equations of motion govern the motion of an object in one, two, or three dimensions. If you ever want to calculate the position, velocity, acceleration, or even time, then these equations are the way to go.
Thefirst equation of motionis
Thesecond equation of motionis
And finally, thethird equation of motionis
In these equations, v is the final velocity, u is the initial velocity, a is the acceleration,t is time, and s is the displacement.
Important! You can’t use these equations for all motions! The above three equations only work for objects with a uniform acceleration or deceleration.
Uniform acceleration:when an object increases its speed at a uniform (steady) rate.
Uniform deceleration:when an object decreases its speed at a uniform (steady) rate.
The graphs below define an object’s uniform acceleration and uniform deceleration.
Also, note that for objects moving with a constant speed and velocity, you don’t need to use the above equations –simple speed and displacement equationsare enough.
Distance = speed ⋅ time
Displacement = velocity ⋅ time
A girl throws a ball vertically upwards with an initial velocity of 20m/s and then catches it sometime later. Calculate the time taken for the ball to return to the same height it was released from.
Solution
We will take anythingmoving upwards as positivein this case.
The distance travelled in the positive and negative direction cancels out because the ball returns to its original position. Hence, thedisplacement is zero.
The final velocity is the velocity at which the girl catches the ball. Since the girl catches the ball at the same height (and provided the air has a negligible effect on the ball), thefinal velocity will be -20m/s(upwards direction positive, downwards direction negative).
For the acceleration, when the ball is tossed upwards, it decelerates due to the gravitational pull, but because the upwards direction is taken as positive, the ball decelerates in the positive direction. As the ball reaches its maximum height and moves downwards, it accelerates in the negative direction. So, when moving down, the acceleration will be -9.81m/s2, which is the constant for gravitational acceleration.
Let’s use the first linear equation of motion: v = u+at
u = 20 m/s
v = -20 m/s
a = -9.81 m/s2
t =?
Plugging in the values yields:
Linear motion is a change in position from one point to another in a straight line in one dimension.
Displacement is a vector quantity, and it is the distance travelled in a specified direction from an initial position to a final position.
A change in displacement over time is velocity.
Average velocity is calculated over the whole duration of motion, whereas instantaneous velocity is calculated for a certain instant of time.
The gradient at any point in time of a displacement-time graph is velocity.
A change in displacement at any point in time is instantaneous velocity.
The rate of change of velocity is acceleration.
A change in velocity at a specific point in time is instantaneous acceleration.
The gradient of a velocity-time graph is acceleration.
When an object increases its speed at a uniform (steady) rate, we say it is moving with uniform acceleration.
When an object decreases its speed at a uniform (steadily) rate, we say it is slowing down with uniform deceleration.
Linear motion is a change in position from one point to another in a straight line in one dimension.
Some examples of linear motion are the motion of a car on a straight road, freefall of objects, and bowling.
No, a rotating object does not produce linear motion. It produces a rotatory movement along its axis.
You can calculate the linear motion of an object by using the three equations of linear motion.
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